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lavg=n∑i=1fili
Where li = actual codeword length of symbol.
$L_{avg} = (0.4)1 + (0.19) \times 3 + (0.16) \times 3 + (0.15)3 + (0.1) \times 3\\ L_{avg} = 2.2 bit/symbol\\ H = \sum\limits_{i = 1}^{n = 5} P_i log = \bigg( \dfrac{1}{P_i} \bigg)\\ H …