(a) The maximum possible optical bandwidth which is equivalent to the maximum possible bit rate (for return to zero pulses) assuming no ISI may be obtained, where:
$B_{opt} = B_T= \dfrac 1{2τ} = \dfrac 1{0.2×10^{-6}} = 5 MHZ$
(b) The dispersion per unit length may be acquired simply by dividing the total dispersion by the total length of the fiber:
Dispersion $= \dfrac {0.1×10^{-6}}{ 15} =6.67 ns \space Km^{-1}$
(c) The bandwidth–length product may be obtained in two ways. Firstly by simply multiplying the maximum bandwidth for the fiber link by its length. Hence:
$B_{opt}L = 5 MHz × 15 km = 75 MHz\space km$
Alternatively, it may be obtained from the dispersion per unit length
$B_{opt}L = \dfrac 1{ 2×6.67×10^{-6}} = 75 MHz\space km$