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A $45^\circ - 45^\circ - 90^\circ$ prism is immersed in alcohol $(n = 1.45)$

written 7.8 years ago by teamques10 ★ 68k

•   modified 4.1 years ago

optical fiber communication

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written 7.8 years ago by teamques10 ★ 68k

Given: $θ_c= 45° \\ n_1 = 1.45$

To find: refractive index $n_2$

Solution:

$θ_c= \sin^{-1} \dfrac {n_2}{n_1} \\ \sin^{-1} \dfrac { n_2}{n_1} = 45° \\ \dfrac {n_2}{n_1} = \sin 45 = 0.707 \\ n_2 = 1.45 * 0.707 \\ = 1.025$

$n_2= $ Minimum refractive index $ = 1.025$

Minimum refractive index $ (n_2)= 1.025$

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