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Find the core radius necessary for single mode operation at 820nm of step index fiber with n1=1.482 and n2=1.474
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Given: λ=820nmn1=1.482n2=1.474V=2.405(single mode step index)

To Find:

1) Core radius (a)

2) Numerical aperture (N.A)

3) acceptance angle (Өa)

4) solid angle (τ)

Solution:

N.A=n21n22=1.48221.4742N.A=0.153

Numerical aperture (N.A)=0.153

V=2πa(N.A)λ2.405=2πa0.153820109a=2.051µm

Core radius (a)=2.051µm

Core radius (a)=2.051µmN.A=sinӨa0.153=sinӨaӨa=8.8°

Acceptance angle (Өa)=8.8°

τ=π(N.A)2=3.14(0.153)2τ=0.073 radians

Solid angle (τ)=0.073 radians

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