Find the core radius necessary for single mode operation at 820nm of step index fiber with $n_1=1.482$ and $n

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Find the core radius necessary for single mode operation at 820nm of step index fiber with

$n_1=1.482$ and

$n_2=1.474$

written 8.1 years ago by

teamques10 ★ 69k

• modified 4.4 years ago

optical fiber communication

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written 8.1 years ago by

teamques10 ★ 69k

Given: $λ =820nm \\ n_1=1.482 \\ n_2=1.474 \\ V = 2.405 \text {(single mode step index)}$

To Find:

1) Core radius (a)

2) Numerical aperture (N.A)

3) acceptance angle (Өa)

4) solid angle (τ)

Solution:

$\Rightarrow N.A = \sqrt{n_1^2-n_2^2 } \\ =\sqrt{1.482^2-1.474^2 } \\ N.A= 0.153$

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