written 7.7 years ago by | • modified 2.8 years ago |
Mumbai University > Mechanical Engineering > Sem 6 > Finite Element Analysis
Marks: 5M
Year: may 2016
written 7.7 years ago by | • modified 2.8 years ago |
Mumbai University > Mechanical Engineering > Sem 6 > Finite Element Analysis
Marks: 5M
Year: may 2016
written 7.7 years ago by |
i) 1-D steady state, heat transfer by conduction
Element matrix equation,
$\frac{KA}{he} \begin{bmatrix} \ 1 & -1 \\ \ -1 & 1 \\ \end{bmatrix} \begin{Bmatrix}\ \theta_1 \\ \ \theta_2 \\ \end{Bmatrix} = \begin{Bmatrix}\ Q_1^2 \\ \ Q_2^2 \\ \end{Bmatrix}$
Where, K = thermal conductivity
A = cross section area
he = length of an element
Q = Heat input
ii) 1 - D, steady state flow of fluid in a pipe.
$\frac{\pi d^4}{128 \mu he} \begin{bmatrix} \ 1 & -1 \\ \ -1 & 1 \\ \end{bmatrix} \begin{Bmatrix} \ \rho_1^e \\ \ \rho_2^e \\ \end{Bmatrix} = \begin{Bmatrix} \ Q_1^e \\ \ Q_2^e \\ \end{Bmatrix}$
Where, $\mu$ = viscosity of fluid
he = length of an element
Q = flow rate (Dischange)
P = pressure