written 8.2 years ago by | • modified 8.2 years ago |
Mumbai University > Electronics and telecommunication engineering > Sem 3 > Analog electronics 1
Marks: 10M
Years: May 16
written 8.2 years ago by | • modified 8.2 years ago |
Mumbai University > Electronics and telecommunication engineering > Sem 3 > Analog electronics 1
Marks: 10M
Years: May 16
written 8.2 years ago by |
It is also called as common drain circuit.
The input is applied to the gate and output is obtained at the source. The source follower amplifier is shown in fig 5.1. Ac equivalent circuit is drawn by connecting drain to ground.
Fig 5.3 shows the small signal equivalent circuit.
For voltage gain A_V: AV=VoVi
Output voltage is measured across ro||RS
Vo=gmVgs(ro||RS)
Vin=Vgs+Vo
Vin=Vgs+gmVgs(ro||RS)=Vgs[1+gm(ro||RS)]
Vgs=Vin(1+gm(ro||RS))
But Vin=Ri(Rsi+Ri) x Vi where Ri = R1||R1
Vgs=((Ri(Rsi+Ri))Vi)(1+gm(ro||RS))
Substitute this into expression for Vo to get,
Vo=((Ri(Rsi+Ri))gm(ro||RS)])(1+〖gm(r〗o||RS)) = (gm(ro||RS)])(1+〖gm(r〗o||RS))(Ri(Rsi+Ri))
Input resistance (Ri):
Ri=R1||R2
Output resistance (Ro): The equivalent circuit to calculate Ro
Ro=VoIo
Apply KCL at node A to get,
Io+gmVgs=Ir+IRS
But Ir=Voro and IRS=VoRS
Io+gmVgs=Vo(1ro+1RS)
Vgs=−Vo
Io=Vo(1ro+1RS)+gmVo=Vo[gm+1ro+1RS]
Ro=VoIo = = 1([gm+1ro+1RS])
Ro=gm||1ro||1RS