Mumbai University > Electronics and telecommunication engineering > Sem 3 > Analog electronics 1

Marks: 10M

Years:May 15

The input impedance at the base emitter by applying KVL is given by:

$Z_b = \frac{V_i}{ I_b} = β r_e + (1+ β) R_E$

The input impedance can also be written as

$Z_b = \frac{V_i}{ I_b} =β ( r_e+ R_E)$

Since $R_E$ is often much greater than $r_e$

$Z_b = β R_E$

= 120 X 0.56 X $10^3$

= 67.2

Calculate the output impedance $Z_o$:

$Z_o = R_C$ = 2.2k

Calculate the voltage gain $A_V$:

$A_V = \frac{V_o}{Vi}$

Refer fig to write,

$V_o = -I_C R_C$

But $I_C = β I_b$

$V_o = -β I_b R_C$

And $V_i= Z_i X I_b= β R_E I_b$

$A_V=\frac{ V_o}{Vi} = \frac{(-β I_b R_C)}{(β R_E I_b )} = \frac{-R_C}{ R_E} = \frac{(-2.2 X 10^3)}{(0.56 X 10^3 )}$= 3.92V