written 8.1 years ago by | • modified 8.1 years ago |
Mumbai University > Electronics and telecommunication engineering > Sem 3 > Analog electronics 1
Marks: 10M
Years: May 15
written 8.1 years ago by | • modified 8.1 years ago |
Mumbai University > Electronics and telecommunication engineering > Sem 3 > Analog electronics 1
Marks: 10M
Years: May 15
written 8.1 years ago by |
AC equivalent circuit:
Let us draw the AC equivalent circuit of voltage divider bias configuration with RE unbiased
Approximate h-parameter equivalent circuit:
Now replace the transistor in the AC equivalent circuit fig by its hybrid equivalent circuit.
Obtain the expression for Ri and R′i:
Ri=VbIb … (1)
But Vb=Ibrπ+IeRE=Ibrπ+(1+β)IbRE
Vb=Ib[rπ+(1+β)RE] ….. (2)
Substituing eq 2 in 1
Ri=(Ib[rπ+(1+β)RE])Ib=rπ+(1+β)RE
Ri=rπ+(1+β)RE
R′i=R1||R2||rπ+(1+β)RE
Obtain the expression of voltage gain AVS:
AVS=VoVs
Vo= Voltage across ( RC||RL)
Vo=−βIb(RC||RL) …. (3)
Now refer circuit Fig4.2,
Vb=IbRi
Substitute this in eq 3
Vo=(−βIb(RC||RL))Ri
But Vb=R′i(R′i+Rs) X VS
Vo=(−βR′iVS)(R′i+RS) X ((RC||RL))Ri
AVS = VoVs = (−βR′i)(R′i+RS) X ((RC||RL))Ri
But Ri=rπ+(1+β)RE
AVS=(−β(RC||RL))(rπ+(1+β)RE) X R′i(R′i+RS)
If R′i>>RSand(1+β)>>rπ then
AVS=(−(RC||RL))RE
This is the expression for voltage gain.
Output resistance:
Let VS = 0, and Vx is connected between the output terminals and current supplied by this source be Ix.
As VS = 0, Ib will reduce to zero. Hence βIb = 0 so the dependent current source is replaced by an open circuit.
Therefore, R′o = VxIx = ( RC||RL)