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For a NPN transistor in CE mode voltage divider bias configuration determine VC and Vs.

Given VCC = +20V, VEE= -20V, Ri = 8.2KΩ, R2 = 2.2KΩ, RC = 2.7KΩ, RE = 1.81KΩ, C1=C2 = 10µF and β = 120.

Mumbai University > Electronics and telecommunication engineering > Sem 3 > Analog electronics 1

Marks: 10M

Years: May 15

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The Thevenin resistance and voltage are determined for the network to the left of the base terminal as shown in fig (a) and (b).

Rth=R1||R2 = 8.2K || 2.2K = 1.73 kΩ

enter image description here

I = $\frac{(V_CC+ V_EE)}{(R_1 + R_2 )} = \frac{(20+ 20)}{(8.2k +2.2k)} = \frac{(40 V)}{(10.4 …

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