For the circuit shown below, calculate $I_DQ$ & $I_DSQ$. It is given that $I_D (ON)$ = 6mA, $V_GS (ON)$ = 8V, $V

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For the circuit shown below, calculate

$I_DQ$ &

$I_DSQ$ . It is given that

$I_D (ON)$ = 6mA,

$V_GS (ON)$ = 8V,

$V_t$ h = 3V.

written 8.2 years ago by

teamques10 ★ 69k

• modified 8.2 years ago

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Mumbai University > Electronics and telecommunication engineering > Sem 3 > Analog electronics 1

Marks: 10M

Years: Dec 15

analog electronics

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written 8.2 years ago by

teamques10 ★ 69k

Step1: Calculate the value of k

k = $\frac{(I_D (on))}{[V_GS (on)- V_TH ]^2}$

$∴k = \frac{(6 X 10^(-3))}{(8-3)^2}$

$∴ k = 0.24 X 10^(-3) \frac{A}{V^2}$

Step2: Obtain I_DQ

$V_GS = V_DD - I_D R_D = 12 - I_D R_D$

We have, $I_DQ$ = $k [V_GS- V_TH ]^2$

Substituting value …

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