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Derive Boundary conditions of Electric field at the boundary of the dielectric media
1 Answer
written 8.2 years ago by |
Tangential component: In order to derive boundary condition at current interface, we will apply ‘Ampere’s law’
∮ˉH.dˉl=Ienclosed=0∫ˉHt1.∆ˉw+∫ˉHt2.∆ˉL+ˉHt2.∆ˉw−ˉHt1.∆ˉL=0ˉHt1.∆ˉw=ˉHt2.∆ˉw=0∫Ht1.∆L=∫Ht2.∆LˉHt1=ˉHt2
Normal components:
For normal components use ∮ˉB.dˉs=∅
-∮B_{n1}.d \bar{s}+∮B_{n1}.d \bar{s}+ ∮B_{n2}.d \bar{s}= ∅ \\ ∮B_{n1}.d \bar{s}= ∮B_{n2}.d \bar{s} ….[θ=90^o-∮B_{n1}.d \bar{s}=0 ,I=0- ∅=0 ] \\ B_{n1}= B_{n2}
The normal component of flux density at current free interface is continuous