written 7.9 years ago by | modified 2.9 years ago by |
Mumbai University > Civil Engineering > Sem 5 > Structural Analysis – II
Marks: 8 Marks
Year: Dec 2014
written 7.9 years ago by | modified 2.9 years ago by |
Mumbai University > Civil Engineering > Sem 5 > Structural Analysis – II
Marks: 8 Marks
Year: Dec 2014
written 7.9 years ago by |
Degree of Indeterminancy , r = 6 – 3 = 3
Number of plastic hinges , n = r + 1 = 3 + 1 = 4
Plastic Hinges Location , N = 6
Number of Independent mechanism = N – r = 6 – 3 = 3
For AB collapse , Θ = δ / 2
Using Work equation ,
ΣP * δ = Σ Mp * Θ
30 * 4 * 2Θ = Mp * Θ + Mp ( Θ + Θ ) + Mp * Θ
240 * Θ = 4 Mp * Θ
Mp = 60 KN-m …………………………………… (1)
For BC collapse ,
ΣP * δ = Σ Mp * Θ
24 * δ = Mp * Θ + Mp ( 2Θ ) + Mp * Θ
48 * Θ = 4 Mp * Θ
Mp = 12 KN-m ……………………………………. (2)
For CD collapse ,
Θ = δ/1 , α = δ / 3
Θ = 3 α
Acc to work equation
ΣP. δ = Σ Mp * Θ
40 * δ = Mp * Θ + 2 Mp * ( Θ + α )
40 * Θ = Mp * Θ + 2 Mp * ( Θ + Θ/3 )
40 * Θ = ( 11 / 3 ) * Mp * Θ
Mp = 10.91 KN-m …………………………………. (3)
Plastic moment = Greatest Mp
From above 3 values , take highest value of Mp ,
Mp = 60 KN-m