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Analyse the rigid jointed plane frame as shown in figure, using moment distribution Method. Draw B.M.D., SFD and elastic curve.
written 7.9 years ago by gravatar for teamques10 teamques10 ★ 69k modified 2.9 years ago by gravatar for pedsangini276 pedsangini276 • 4.8k

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Mumbai University > Civil Engineering > Sem 5 > Structural Analysis – II

Marks: 10 Marks

Year: May 2015
structural analysis
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written 7.9 years ago by gravatar for teamques10 teamques10 ★ 69k

It is a Non – Sway Frame.

Fixed End Moments :

FE MAB = Wab² / L² = 20 * 2 * 3² / 5² = 14.4 KN-m

FE MBA = - Wa²b / L² = 20 * 2² * 3 / 5² = -9.6 KN-m

FE MBC = FE MCB = WL² / 12 = 10 * 4² / 12 = 13.33 KN-m

FE MBD = FE MDB = WL / 8 = 30 * 3 / 8 = 11.25 KN-m

Distribution Factor & K :

Joint A ,

AB = 0 = K = DF

Joint B ,

BA = 1 / L = 1 / 5 = 0.2 I = K , DF = 0.28

BC = 3 I / 4 L = 3 I / 4 * 4 = 0.1875 I = K , DF = 0.26

BD = 1 / L = 1 / 3 = 0.33 I = K , DF = 0.46

ΣK = 0.71715 I

Joint C ,

1 = K , DF = 1

Joint D ,

DB =0 = K = DF

Moment Distribution Table :

enter image description here

enter image description here
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