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Determine .

Determine the horizontal of joint D of the rigid jointed plane frame as shown in fig.,due to change of temp.of member surfaces.Consider depth of all the members as 500mm.Take $\alpha_t=12 \times 10^{-6}/^0$

Mumbai University > Civil Engineering > Sem 5 > Structural Analysis – II

Marks: 10 Marks

Year: May 2015

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Apply unit weight of 1 KN at D ,

Apply condition of equation,

$ΣMA = 0 \\ -1 * 3 + MA = 0 \\ MA = 3 KN-m \\ ΣFY =0 \\ VA = 0 \\ ΣFX = 0 \\ -HA + 1 = 0 \\ HA = 1$

h = depth of all members = 500 mm = 0.5 m

Members Tc Δt Δt / h Axial Force,(N) Area,in,m²,(A)
AB 20 + ( 40 -20) / 2 = 30°c 40 -20 = 20°c 20 / 0.5 = 40 0 -,½ * 3 * 3 +,½ * 2 * 2 = 2.5
BC 15 + (30 -15) / 2 = 22.5°c 30 - 15 = 15°c 15 / 0.5 = 30 1 2 * 4 = 8
CD 10 + (20-10) / 2 = 15°c 20 - 10 = 10°c 10 / 0.5 = 20 0 ½ * 2 * 2 = 2

Apply Mohr’s Equation ,

Displacement $= αt * Σ [ ( Δt / h ) * A + tc * N * L ] \\ = 12̂ * 10^-6 [ ( 40 * -2.5 + 30 * 0 ) + ( 30 * 12 + 22.5 * 1 * 4 ) + (20 * 2 + 15 * 0 ) ] \\ = 5.16 * 10 ^ -3 m = 5.16 mm$

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