Mumbai University > Civil Engineering > Sem 7 > Quantity Survey Estimation and Valuation

Marks: 8 Marks

Year: May 2015

Assume 10 cu m of brickwork

1 cu m = 500 no of bricks

10 cu m = 5000 no of bricks

Volume of one brick $= 0.19*0.09*0.09 = 1.539*10^{-3}$

Total volume $= 5000*1.539*10^{-3} = 7.695 cu m$

Dry volume of mortar = 10-7.695 = 2.305 cu m

Wastage = 1.2*2.996 = 3.596 cu m

Cement $= \dfrac{3.596}{(1+4)} = 0.7192$

No of cement bags $= \dfrac{0.7192}{0.035} = 20.54 = 21$ bags

Sand = 0.7192*4 = 2.87 cu m

Final Cost = Rs. 5640/ cu m