written 7.8 years ago by
teamques10
★ 67k
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modified 5.2 years ago
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$\text{Trapezoidal portion} \\
V= \bigg(\dfrac{A1+A2}{2}\bigg) *H \\
= \bigg(\dfrac{0.38*0.38+1.2*1.27*0.4}{2}\bigg) \\
= 0.333 m²$ $\hspace{5cm}$ $\text{Trapezoidal portion} \\
V= \bigg(\dfrac{A1+A2}{2}\bigg) *H \\
= \bigg(\dfrac{0.38*0.48+1.2*1.37*0.5}{2}\bigg) \\
= 0.456 m²$
$\text{Rectangular portion} \\
= 1.2*1.27*0.15 \\
= 0.22 m³ \\
VF1 = 0.333+0.22 \\
= 0.553 m³$ $\hspace{7.5cm}$ $\text{Rectangular portion} \\ = 1.2*1.37*0.15 \\ = 0.246 m³ \\ VF2 = 0.456 + 0.246 \\ = 0.702 m³$
Step 1:-
Total cl $= 3.46*6+2.48*3+2.73*5+2.6+2.63*2+2.78*2+1.8+1.23*2+4.23*2+4.98+2.3*2 \\
= 77.57$
No of junction = 12
Step 2:-
Prepare an abstract sheet for above question