written 8.0 years ago by | • modified 8.0 years ago |
Mumbai University > Civil Engineering > Sem 5 > Applied Hydraulics 1
Marks: 10M
Year: Dec 14, May 15, Dec 15
written 8.0 years ago by | • modified 8.0 years ago |
Mumbai University > Civil Engineering > Sem 5 > Applied Hydraulics 1
Marks: 10M
Year: Dec 14, May 15, Dec 15
written 8.0 years ago by |
Moment of momentum equation is derived from moment of momentum principle which states that the resulting torque acting on a rotating fluid is equal to the rate of chance of moment of momentum.
Let $V_1$ = velocity of fluid at section 1
$r_1$ = radius of curvature at section 1
Q = rate of flow of fluid
$\rho$ = density of fluid
and $V_2$ and $r_2$ = velocity and radius of curvature at section 2
Momentum of fluid at section 1 = mass x velocity = $P Q \times V_1 /s$
Moment of momentum per second at section 1 = $PQ \times V_2 \times r_2$
Rate of change of moment of momentum = $PQ V_2 r_2 - PQV_1 r_1 = PQ[v_2r_2 - v_1r_1]$
According to moment of momentum principle
Resultant torque = rate of change of moment of momentum
$T = PQ [V_2r_2 - V_1r_1]$ ----- (1)
Eq (1) is known as moment of momentum equation.