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One side of metallic plate absorbs a heat flux of 1000 Wm2. Its other side is insulated.The emissivity of surface is 0.8 and convective heat transfer coefficient is 20 Wm2K

Ambient is maintained at 300K. Determine the temperature of plate under steady state conditions σ=5.67×10(8)

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qr=1000w/m2 ,hc=20W⁄(m2 K,ε=0.8,T=27℃=300K)

Analysis: The radiant heat flux absorbed by the plate,will be dissipated by convection and radiation.

Thus,

qr=hc (TsT )+εσ(T4sT4 )

Using the numerical values,

1000=20(Ts300)+0.8×5.67×10(8) (T4s3004 )

Ts=338.57K

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