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The forced convection heat transfer phenomenon can be influenced by the variables given in following table.
These seven variables are expressed in four primary dimensions (M,L,T,t) therefore, according to Buckingham pi theorem, the independent dimensionless group are:
= no. of variable affecting the phenomenon – No. of primary dimensions used.
=7−4=3(i.e.π1,π2,π3)
Writing these three group as,
π1=Daρbμckdfu∞,
π2=DeρfμgkhfCP,
π3=Diρjμkklfh
Where D,,ρ,μ,kf from a core group(repeating variable) and u∞Cp and h are as selected variable.
Since the groups π(1,)π2,π3 are dimensionless hence certain exponents are applied on the repeating variable, which are to be determined,
Expressing the variable in their primary dimensions for π(1,)
π1=La(ML(−3))b(ML(−1)t(−1))c(MLt(−3)T(−1))d(Lt(−1))
M0L0T0t0=M(b+c+d)L(a−3b−c+d+1)T(−d)t(−c−3d−1)
Separating the exponents for dimensional homogeneity
M=b+c+d=0
L=a-3b-c+d+1=0
T=-d=0
t=-c-3d-1=0
Solving these simultaneous equations, we get
D=0,c=-1,b=1,a=1
Hence the dimensionless group is formed is
π1=(Dρu∞)μ=ReD (Reynolds number) Expressing the primary dimension for variables of π2, π2=Le(ML(−3))f(ML(−1)t(−1))g(MLt(−3)T(−1))h(L2t(−2)T(−1))1
Separating the exponents for dimensional homogeneity.
M:0=f+g+h
L:0=e-3f-g+h+2
T:0=-h-1,
t:0=-g-3h-2
Solving these simultaneous equations, we get
H=-1,g=1,f=0,e=0
Hence the dimensionless group formed is,
π2=(μCP)kf =Pr(Prandtl Number)
Expressing the primary dimension for variables for π3, π3=Li(ML(−3))j(ML(−1)t(−1))k(MLt(−3)T(−1))l(Mt(−3)T(−1))
M:0=j+k+l+1,
L:0=i-3j-k+l,
T:0=-l-1,
t: 0=-k-3l-3
Solving these simultaneous equations, we get
L=−1,k=0,j=0,i=1
Hence the dimensionless group formed is,
π3=hDkf =NuD (Nusselt number)
Hence for forced convection,
NuD=φ(ReD,Pr)
hence proved.