A spring of stiffness k is placed horizontally and a ball of mass m strikes the spring with a velocity v. Find the maximum compression of the spring. Take m = 5 kg, k = 500 N/m, v = 3m/s

1.6kviews

written 7.9 years ago by

teamques10 ★ 68k

modified 2.8 years ago by

pedsangini276 • 4.8k

Mumbai University > FE > Sem 1 > Engineering Mechanics

Marks : 06

Years : DEC 2015

engineering mechanics

ADD COMMENT EDIT

1 Answer

25views

written 7.9 years ago by

teamques10 ★ 68k

enter image description here

Given:-

$m=5kg \\ v=3m/s \\ k=500N/m$

To find:-

Maximum compression (x or $\delta$ )

Solution:-

Using work energy principle,

(Kinetic energy of ball) = (potential energy of compressed spring)

$\therefore \dfrac 12 mv^2 = \dfrac 12 k\delta^2 \\ \therefore \delta =\sqrt{\dfrac mk} v \\ =\sqrt{\dfrac {5}{500}}.3 \\ \therefore \delta =0.3m \Rightarrow Ans$

ADD COMMENT EDIT

Please log in to add an answer.