A spring of stiffness k is placed horizontally and a ball of mass m strikes the spring with a velocity v. Find the maximum compression of the spring. Take m = 5 kg, k = 500 N/m, v = 3m/s

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written 8.2 years ago by

teamques10 ★ 69k

modified 3.1 years ago by

pedsangini276 • 4.8k

Mumbai University > FE > Sem 1 > Engineering Mechanics

Marks : 06

Years : DEC 2015

engineering mechanics

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written 8.2 years ago by

teamques10 ★ 69k

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Given:-

$m=5kg \\ v=3m/s \\ k=500N/m$

To find:-

Maximum compression (x or $\delta$ )

Solution:-

Using work energy principle,

(Kinetic energy of ball) = (potential energy of compressed spring)

$\therefore \dfrac 12 mv^2 = \dfrac 12 k\delta^2 \\ \therefore \delta =\sqrt{\dfrac mk} v \\ =\sqrt{\dfrac {5}{500}}.3 \\ \therefore \delta =0.3m …

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