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The crank BC of a slider crank mechanism is rotating at constant speed of 30rpm clockwise.

Determine the velocity of the piston A at the given instant.

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1 Answer
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Angular Velocity of the rod CB,

ωCB=2πN60=2×3.14×3060ωCB=3.14rad/sVB=CB×ωCB=100×3.14=314mm/s

I is obtained by taking perpendicular from VA and VB

In ABCABsin120=BCsinBAC=ACsinABC400sin120=100sinBACBAC=12.500ABC=18012012.500=47.50400sin120=ACsin47.5AC=340.53mmIn  ACI(ACI is 300600900 triangle)ACsin30=AIsin60=CIsin90340.53sin30=AIsin60=CIsin90AI=589.8      CI=681.06EI=100+681.06=781.06

Angular velocity of the rod AB,

ωAB=VBBI=314781.06=0.402rad/sec

Instantaneous velocity of A,

VA=r.ωAB=IA.ωAB=589.8×0.402VA=237.2mm/s

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