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Collar B moves up with constant velocity $V_B=2 m/s$ . Rod AB is pinned at B. Find out angular velocity of AB and velocity of A.

written 7.9 years ago by teamques10 ★ 68k

modified 2.8 years ago by pedsangini276 • 4.8k

Mumbai University > FE > Sem 1 > Engineering Mechanics

Marks : 06

Years : MAY 2013

engineering mechanics

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written 7.9 years ago by teamques10 ★ 68k

$IB=2420mm \\ IA=1860mm \\ V_A = \dfrac {IA}{IB}.V_B \\ = \dfrac {1860}{2420} ×2 \\ \therefore V_A=1.537 m/s \Rightarrow Ans$

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