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For a vehicle moving along a straight line, v-t diagram is as shown in fig. below. Plot a-t and s-t diagrams for the given time period.

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1 Answer
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$$S_0=0m$$

$S_5=S_0+A[ABGF] \\ S_5=0+5×5 \\ S_5=25 m$

enter image description here

$S_{15} = s_5+A[BDE]+A[BDHG] \\ S_{15} =25+\dfrac 12×10×15+10×5 \\ S_{15}=150 m$

enter image description here

a = (slope V. t Curve)

For 0 to 5 sec

a=slope $= \dfrac {v_2-v_1}{t_2-t_1} \\ = \dfrac {5-5}{5-0} \\ =0$

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For 5 to 15 sec

a=slope $=\dfrac {v_2-v_1}{t_2-t_1 }= \dfrac {20-5}{15-5}=1.5 m/s$

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