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Find the angle the force P makes with horizontal such that the block of mass 4 kg has an acceleration of 10m/sec2,

when it is subjected to a force of 35N.μs=0.7,μk=0.6

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Given:

μA=0m/s,μB=0m/stA=tB+5,aB=5m/s2S=500m,aA=?

Ans:

S=ut+12at2

For Car B,

sB=uB.tB+12aB.t2B500=0+12×5×t2Bt2B=200tB=14.14sec

For Car A,

tA=tB+5=19.14secSA=uA.tA+12aA.t2A500=0+12aA×19.142aA=2.73m/s2

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