A particle moves in a straight line with acceleration-time diagram as shown in figure

2.2kviews

written 8.2 years ago by

teamques10 ★ 69k

• modified 4.9 years ago

Construct Velocity time diagram for the motion assuming that the motion starts with initial velocity of $5m/s$ from the starting point. Also determine its displacement at $t=12 sec.$

enter image description here

engineering mechanics

ADD COMMENT EDIT

1 Answer

148views

written 8.2 years ago by

teamques10 ★ 69k

enter image description here

Velocity Diagram:

$V_6=V_0+ A(∆AOB) \\ =5 + \dfrac 12 ×6 ×1 \\ =8 m/s \\ V_{12} = V_6+ A (∆BCN) \\ =8+ \dfrac 12 ×6 ×2 \\ =14 m/s$

enter image description here

Displacement diagram:

$S_6=S_0+ A (GEIM)+ A(EIF) \\ =42+6 ×8 + \dfrac 13 ×6×6 \\ =102 m$

Displacement at t= …

Create a free account to keep reading this post.

and 3 others joined a min ago.

ADD COMMENT EDIT

Please log in to add an answer.