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A force of magnitude 500 N is acting from A (2, 3, 6) and passes through a point B(6, 2, 6). Compute its moment about point C (4, 6, 3).

written 7.9 years ago by teamques10 ★ 68k

•   modified 4.5 years ago

engineering mechanics

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written 7.9 years ago by teamques10 ★ 68k

•   modified 7.9 years ago

$\bar {F_{AB}} = F_{AB} × \hat {AB} = 500× \dfrac {(6-2)i+(2-3)j+(6-6)k}{\sqrt{(6-2)^2+(2-3)^2+(6-6)^2 }} \ \bar {F_{AB}} = 485.07 i ̅-121.27 j ̅+0 k ̅ $ Moment, $\begin {vmatrix} i&j&k \ 2&3&-3 \ 485.07 &-121.27 &0 \ \end {vmatrix}$ $= -363.8 i ̅+1455.21 j ̅-1697.75 k ̅$

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