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A force of magnitude 500 N is acting from A (2, 3, 6) and passes through a point B(6, 2, 6). Compute its moment about point C (4, 6, 3).
1 Answer
written 8.2 years ago by | • modified 8.2 years ago |
¯FAB=FAB×^AB=500×(6−2)i+(2−3)j+(6−6)k√(6−2)2+(2−3)2+(6−6)2 ¯FAB=485.07i̅−121.27j̅+0k̅ Moment, |ijk 23−3 485.07−121.270 | =−363.8i̅+1455.21j̅−1697.75k̅