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Find force requires to pull block B as shown, Coefficient of friction between A and B is 0.3 and between B and floor is 0.25. Mass of A=40kg and B=60kg.

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FBD- Block A

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$∑f_x =0 \\ 0.3 R_1-T \cos⁡30=0 (1) \\ ∑f_y =0 \\ R_1+ T \sin 30=40 ×9.81 (2) $

From equation (1) and (2)

$R_1=334.47 N \\ T=115.86 N $

FBD – Block B

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$ ∑f_y =0 \\ R_2=R_1+ 60×9.81=334.47+60 ×9.81 \\ R_2=923.07 N \\ ∑f_x =0 \\ P=0.3 R_1+ 0.25 R_2 \\ P=0.3 ×334.47+0.25 ×923.07 \\ P=331.108 M $

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