A block of weight 800N is acted upon by a horizontal force P as shown in figure. If the coefficient of friction between the block and inclined are

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written 8.3 years ago by

teamques10 ★ 69k

• modified 4.9 years ago

$μ_s=0.35$ and $μ_k=0.25,$ determine the value of P for imending motion up the plane.

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engineering mechanics

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written 8.3 years ago by

teamques10 ★ 69k

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$∑f_x =0 \\ P- μR \cos 25-R \sin⁡25=0 →(1) \\ ∑f_y =0 \\ -μR \sin 25+R \cos25-800=0 \\ R=1054.86 N$

From equation (1),

$P=0.35×1054.86 \cos⁡25+ 1054.86 \sin⁡25 \\ P=780.41 N$

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