$∑f_x=0⟹H_A=50 \cos 60 \\ H_A=25N (→) \\ M_A=0 \\ ∴ -60×4-8×50 \sin 60-180+R_E×14=0 \\ R_E=54.74 N (↑) \\ ∑f_y=0 ⟹ V_A+R_E=60+50 \sin 60 \\ V_A=48.56N \\ ∴R_A = \sqrt{25^2+48.56^2 } \\ ∴R_A=54.62 N \space\space and \space\space θ = \tan^{-1} (\dfrac {48.56}{25})=62.76^0$

Topic: Analysis of plane Truss.