Load due to rectangular UDL $= 24 ×3=72 KN$

acts at 1.5 m from D.

Load due to triangular UVL $= \dfrac 12 ×24×3=36KN $

acts at 1/3×3=1 m from F.

Since Beam AB is in equilibrium,

$∑M_A=0 \\ -1 ×1.5-72 ×5.5+18+R_B ×9-36 ×11=0 \\ 9 R_B=775.5 \\ R_B=86.1667 KN (↑) \\ ∑ f_x= 0 \\ R \cos⁡ θ=0\space\space\space\space\space θ= 90^\circ \\ ∑f_y=0 \\ R_A \sin⁡ θ-1-72+R_B-36=0 \\ R_A \sin 90=1+72-86.1667+36 \\ R_A=22.8333 KN (↑) $