Determine the resultant of the forces acting as given in figure below. Find the angle which the resultant makes with the positive X-axis.

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written 7.7 years ago by

teamques10 ★ 66k

• modified 4.3 years ago

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engineering mechanics

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1 Answer

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written 7.7 years ago by

teamques10 ★ 66k

• modified 7.7 years ago

$$∑f_x=50 \cos 60+70 \cos 45+25 \cos 60=86.99 N $$ $$ ∑f_x=50 \sin 60+70 \sin 45-25 \sin 60-20=51.15 N $$

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Resultant

$R=\sqrt{(∑f_x )^2+(∑f_y )^2 } \\ =\sqrt{86.99^2+51.15^2} \\ R = 100.91 N \\ θ= \tan^{-1}(\dfrac {∑f_y}{∑f_x}) = \tan^{-1}⁡( \dfrac {51.15}{86.99}) \\ θ=30.455^0 $

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