Three Concurrent forces $P=150N, Q=250N$ and $S=300N$ are acting at $120^\circ$ with each other. Determine their resultant force magnitude and direction with respect to P. What is their equilibrant?

6.5kviews

Three Concurrent forces

$P=150N, Q=250N$ and

$S=300N$ are acting at

$120^\circ$ with each other. Determine their resultant force magnitude and direction with respect to P. What is their equilibrant?

written 8.2 years ago by

teamques10 ★ 69k

• modified 4.9 years ago

engineering mechanics

ADD COMMENT EDIT

1 Answer

642views

written 8.2 years ago by

teamques10 ★ 69k

enter image description here

$∑f_x =150-250 \cos 60-300 \cos 60= -125N \\ ∑f_y=250 \sin 60-300 \sin 60= -43.3 N$

Resultant,

$R=\sqrt{(∑f_x )^2 + (∑f_y )^2} \\ R=\sqrt{(-125)^2+ (-43.3)^2} =132.28 N$

enter image description here

$θ= \tan^{-1} (\dfrac {-125}{-43.3}) = 70.89^\circ$

ADD COMMENT EDIT

Please log in to add an answer.