Find the acid-value of vegetable oil whose 5ml required 2ml of N/10 KOH during titration (Density of oil = 0.92).

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teamques10 ★ 69k

• modified 8.0 years ago

FE > Semester 1 > Applied Chemistry 1

Marks : 04

Years : DEC 2015

engineering chemistry

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written 8.0 years ago by

teamques10 ★ 69k

Wt of oil = vol in ml $\times$ density

$=5 \times 0.92\\ = 4.6 gms $

Normality of $KOH = N/10 = 0.1N$

Volume of $KOH = 2 ml$

Acid value $=\dfrac {\text {Vol of KOH×N×56}}{\text {wt of oil in gms}} \\ =\dfrac {1×0.1×56}{4.6} \\ =2.4348 mgs \space \space KOH$

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