Find the acid value of vegetable oil whose 5 ml requires 2ml of N/100 KOH during lubrication(density of oil =0.92g/ml)

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written 7.8 years ago by

teamques10 ★ 67k

• modified 7.8 years ago

FE > Semester 1 > Applied Chemistry 1

Marks : 03

Years : MAY 2016

engineering chemistry

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written 7.8 years ago by

teamques10 ★ 67k

Weight of oil=volume in ml * density $= 5*0.92 = 4.6 \text {gms}$

Normality of $KOH= N/100 = 0.01 N$

Volume of $KOH = 2ml$

ACID VALUE $= \dfrac {\text {vol.of KOH required X Normality of KOH}\times 56}{\text {weight of oil in gms}} \\ = \dfrac {2 \times 0.01 \times 56}{4.6} \\ = 0.2434 \text {mgs KOH }$

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