Find the acid value of vegetable oil whose 5 ml requires 2ml of N/100 KOH during lubrication(density of oil =0.92g/ml)

1.7kviews

written 8.3 years ago by

teamques10 ★ 69k

• modified 8.3 years ago

FE > Semester 1 > Applied Chemistry 1

Marks : 03

Years : MAY 2016

engineering chemistry

ADD COMMENT EDIT

1 Answer

61views

written 8.3 years ago by

teamques10 ★ 69k

Weight of oil=volume in ml * density $= 5*0.92 = 4.6 \text {gms}$

Normality of $KOH= N/100 = 0.01 N$

Volume of $KOH = 2ml$

ACID VALUE $= \dfrac {\text {vol.of KOH required X Normality of KOH}\times 56}{\text {weight of oil in gms}} \\ = \dfrac {2 \times 0.01 \times 56}{4.6} \\ = 0.2434 \text {mgs KOH }$

ADD COMMENT EDIT

Please log in to add an answer.