The hardness of 75,000 litres of a water sample was completely removed by a permutit.

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written 8.3 years ago by

teamques10 ★ 69k

• modified 8.3 years ago

The exhausted permutit then required 1500L of NaCl containing 117mg of NaCl per litre for regeneration. Calculate the hardness of water sample.

FE > Semester 1 > Applied Chemistry 1

Marks : 04

Years : DEC 2015

engineering chemistry

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written 8.3 years ago by

teamques10 ★ 69k

• modified 8.3 years ago

$117mg \text { of } NaCL = 1 \text {Litre}$

$1500$ liters solution contains $= 1500 x 117 = 175500mg$ of NaCL

Now,

$CaCO_3$ equivalent $= 175500×\dfrac {100}{2×58.5}=15×10^4 \text {mg of } CaCO_3/ ppm$

$∴75×10^3 \text { litre} →x$

$∴x=15×75×10^7 \ =1125×10^7$

Hardness of water sample $= 1125 \times 10^7$

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