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Calculate the quantity of pure lime (70% pure) and soda (85%pure) required for softening of 100,000 litres of water containing the following impurities in ppm
written 7.8 years ago by gravatar for teamques10 teamques10 ★ 67k •   modified 7.8 years ago

${Ca(HCO_3)_2=30.2, Mg(HCO_3)_2=20.8, CaCl_2=28.1, MgCl_2=8.78, CaSO_4=35, MgSO_4=6.7, NaCl=17.9 }$

FE > Semester 1 > Applied Chemistry 1

Marks : 06

Years : DEC 2015
engineering chemistry
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written 7.8 years ago by gravatar for teamques10 teamques10 ★ 67k

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Lime $=\dfrac {74}{100} (18.64+2×14.25+9.24+25.73)×\dfrac {100}{70}×10^5 \\ =\dfrac {74}{70} (82.11)×10^5 \\ =86.802×10^5 \\ \text {Soda} = \dfrac {106}{100} (25.31+9.24+5.58)×\dfrac {100}{85}×10^5 \\ =\dfrac {106}{85}×40.13×10^5 \\ =50.044×10^5$
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