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What is the probability of an electron being thermally promoted to the conduction band in a diamond at 270C, if the band gap is 5.6 eV wide?

Mumbai University > First Year Engineering > Sem 1 > Applied Physics 1

Marks: 3M

Year: May 2016

1 Answer
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Given:

T1=270C=300K

ER=5.6eV=5.6x1.6x1019J

Find:

f(Ec)

Solution:

The probability that an electron being thermally promoted to the conduction band is given as

f(Ec)=11+exp(Eg2KT)

where k is the Boltzmann constant.

Substituting the given data for ER, T, k into above equation, we get

f(Ec)=11+exp(5.6×1.6×10192×1.38×1023×300)

f(Ec)=1.7×1047

Since the probability f(Ec) is extremely small, electrons cannot be thermally promoted to the conduction band of diamond at 270C.

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