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It was found that in a class, 80 students are passed in English, 60 in Science and 50 in Mathematics. It was also found that 30 students passed in both English and Science, 15 students passed in both

(i) How Many students passed in at least one subjects. - (ii) How many students passed in English only? - (iii) How many students failed in all three subjects? -

Mumbai University > Computer Engineering > Sem 3 > Discrete Structures

Marks: 8 Marks

Year: Dec 2015

1 Answer
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Let A denotes students passed in English.

B denotes students passed in Science.

and C denotes students passed in Mathematics.

|A| =80

|B| =60

|C| =50

|AՈB| =30

|AՈC| =15

|BՈC| =20

|A U B U C|=150

|AՈBՈC| =10

Students passed in at least one subjects

=|AՈB|+|AՈC|+|BՈC|

=30+15+20

=65

Hence, students passed in atleast one subject are 65

Students passed in English only

Passed in English only=|A|-[|AՈB|+|AՈC|+

=|A|-[|B|+|C|-|B Ո C|+|AՈBՈC|]

=80-[30+15+10]

=25

Hence, students passed in English only are 25.

Students failed in all three subjects

|A ̅ՈB ̅ՈC ̅|=150-(80+60+50) + (30+15+20)-10=60-62+20-2=10

So, 10 students failed in all three subjects.

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