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Determine the $V_{GSQ},I_{DQ}$ and $V_{DSQ}$ and $A_V$ for a voltage divider ciruit with $V_{DD}= 18v,R_D= 2.2K,R_1=2.1M,R_2=330K$ and $R_S=1.2 K,I_{DSS}=10mA,V_P=-8V$ and $I_FS=40\mu s$.
written 7.9 years ago by gravatar for teamques10 teamques10 ★ 68k modified 2.8 years ago by gravatar for pedsangini276 pedsangini276 • 4.8k

Mumbai University > Computer Engineering > Sem 3 > Electronic Circuits and Communication Fundamentals

Marks: 10 Marks

Year: Dec 2013
electronic circuits and communication
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written 7.9 years ago by gravatar for teamques10 teamques10 ★ 68k •   modified 7.9 years ago

$V_{DD}= 18v \\ R_D= 2.2K \\ R_1= 2.1M \\ R_2 = 330K \\ R_S = 1.2 K \\ I_{DSS} = 10mA \\ V_P = — 8V \\ I_{FS}=40µs.$

Find

  1. $V_{GSQ}$
  2. $I_{DQ}$
  3. $V_{DSQ}$

Solution

  1. $V_{GSQ}=\bigg(\dfrac{R_2}{R_1+R_2 }\bigg) V_{DD}=2.44 V$
  2. $I_{DQ}=\bigg(\dfrac{R_2}{R_1+R_2}\bigg) I_{DSS}=24.3 mA$
  3. $V_{DSQ} =V_{DD}-I_{DQ} R_D=17.94 V$
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