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Find the Energy of the signal x(n) = 0.5*u(n) + 8nu(-n-1)
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The total energy of a sequence x[n] is defined by,

Ex=n=|x[n]|2

Ex=|u(n)2+8nu(n1)|2

Ex=|u2(n)4|+|2u(n)8nu(n1)|+|8nu(n1)|2

We know, u(n)=1;n0=0;n<0

, u(-n-1) =1;n<1=0;n0

Ex=140|u2|+0+1|82n|

Substituting n=m,

Ex=14+0+1|64m|

,Ex=∴14+0+1|164m|

m=m=1am=a1a

,Ex=14+0+(164)(1164)

,Ex=14+0+163=67252

Result: Energy of the given signal x(n) is, Ex=67252

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