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Find the probabilistic inference by enumeration of entries in a full joint distribution table shown in figure 1. (i) No cavity when toothache is there (ii) p(Cavity! toothache or catch)
written 8.0 years ago by gravatar for teamques10 teamques10 ★ 68k •   modified 4.6 years ago

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soft computing
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written 8.0 years ago by gravatar for teamques10 teamques10 ★ 68k

  1. No cavity when toothache is there

    P(¬cavity|toothache) $= P(¬cavity^toothache) / P(toothache) \\ = (0.016 + 0.064) / (0.108 + 0.012 + 0.016 + 0.064) \\ = 0.4$

  2. p(Cavity|toothache or catch)

    $= P(Cavity|toothache) + p(catch) \\ = [P(cavity \hat toothache) / P(toothache)] + P(catch) \\ = [(0.108+0.012)]/[(0.108+0.012+0.016+0.064 + (0.108+0.016+0.072+0.144) \\ = 0.96$
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