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Convert the followed propositional logic statement into CNF A-> (B<->C)
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written 7.9 years ago by |
A -> (B<->C) //KB
= ~A | (B<->C) //Eliminating Implication
= ~A | [(~B | C) & (B |~C)] // Eliminating bidirectional Implication
= [~A | (~B | C)] & [~A | (B |~C)] // Distributing & over |
= (~A | ~B | C) & (~A | B |~C ) // Flattening nested conjuncts & disjuncts
≈ (¬A v ¬B v C) ^ (¬A v B v ¬C )