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Find the inverse Laplace transform of s2s(s+1)3

Mumbai University > EXTC > Sem 4 > Signals and Systems

Marks : 05

Year : DEC 2014

1 Answer
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By partial fraction,

x(s)=As+B(s+1)+C(s+1)2+D(s+1)3A=x(s)× s=s2(s+1)3|s=0=2D=x(s)×(s+1)3=s2s|s=1=3C=x(s)×(s+1)3

Differentiating w.r.t s

=dds(s2s)=2s2|s=1=2B=x(s)×(s+1)3

Differentiating w.r.t s two times

=12!d2ds2(s2s)=2s3|s=1=2x(s)=2s+2(s+1)+2(s+1)2+3(s+1)3

By Inverse Laplace transform,

x(t)=2u(t)+2etu(t)+2et(t)+32etu(t).

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