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Find out even and odd component of the following signal

x[t]=cos2[πt2]

Mumbai University > EXTC > Sem 4 > Signals and Systems

Marks : 05

Year : DEC 2015

1 Answer
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x[t]=cos2πt2 x[t]=1+cos2π2t2cos2A=1+cos2A2 x[t]=12+12cosπt Compare the equation with x[t]=A+Acos(2πft) 2πft=πt f=12 T=2 Even part of the signal is given by xe(t)=12[x(t)+x(t)] Now,x(t)=12+12cos(πt) =12+12cosπt xe(t)=12[12+12cosπt+12+12cosπt] xe(t)=12+12cosπt Odd part of the signal is given by xo(t)=12[x(t)x(t)] =12[12+12cosπt1212cosπt] xo(t)=0

Even and odd components of the signal are shown in the figure below:

enter image description here

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