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Determine whether the signals are power or energy signals. Calculate energy/power accordingly:
1 Answer
written 8.1 years ago by | • modified 5.9 years ago |
(i) $x(t) = 0.9e^{-3t} u(t)$
$E = ∫\limits_{-∞}^∞|x(t) |^2 dt $
$ =∫\limits_{-∞}^∞|0.9e^{-3t} u(t) |^2 dt \\ = 0.81∫\limits_0^∞e^{-6t} dt \\ = 0.81[\dfrac {e^{-6t}}{-6}]^{\infty}_0 \\ = 0.81/6 \\ E= 0.135J$
Since the signal is not periodic hence it’s not a power signal but it is a energy signal.
(ii) $ …