written 8.2 years ago by |
Jot down the data provided in the question.
Calculate :- $H^2⁄Dt$ with the help of given data.
Now from IS code :- 3370 (part 4 )-1967 search in Table 9 page 35
The coefficient at that particular value of $H^2⁄Dt$ to calculate Hoop tension
Hoop tension T= coefficient × WHR
$Astr = \dfrac T{σst}, Ast min$
Decide spacing and then calculate the final area provided
Apply a check this point:-
$σct=\dfrac T{1000 t+(m-1) Ast_p}$
Which should be less than the σct of that particular grade provided for design.
Vertical steel:
Again form same IS code Page.36 Table 10
Calculate the coefficient for both near side (-ve) as well as for side (+ve)
$BM=Coefficient ×WH^3 \\ Ast= \dfrac {BM}{σctjd} j=0.85$
Decide the diameter & than calculate the spacing.
Apply a shear check for its safety from same IS code page 37 table 11
pick out the coefficient for the value of $ H^2⁄Dt$ and put in the following formula.
$→ V=Coefficient ×WH^2 \\ → pt (\% steel) \\ → Z_c (page 91 IS 456-2000) \\ V_c=K\space \space Z_c bd\\ V_c\gt V (\text {Then it will be a safe design}.)$
Reinforcement details:-
Distribution steel is calculated using Ast min.