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Calculate the numerical aperture of a fiber with core index n1=1.61 and cladding index n2=1.55

Mumbai university > FE > SEM 2 > Applied Physics II

Marks: 3M

Year: Dec 2013

1 Answer
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Given:-

n1=1.61

n2=1.55

To find:

Numerical Aperture (NA)

Solution:

NA=n21n22

NA=(1.61)2(1.55)2

NA=0.435

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