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Calculate the numerical aperture of a fiber with core index $n_1 = 1.61$ and cladding index $n_2 = 1.55$

written 8.2 years ago by teamques10 ★ 68k

•   modified 8.2 years ago

Mumbai university > FE > SEM 2 > Applied Physics II

Marks: 3M

Year: Dec 2013

advanced engineering physics

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written 8.2 years ago by teamques10 ★ 68k

Given:-

$n_1 = 1.61$

$n_2 = 1.55$

To find:

Numerical Aperture (NA)

Solution:

$NA = \sqrt{n_1^2 - n_2^2}$

$NA = \sqrt{(1.61)^2 - (1.55)^2}$

$NA = 0.435$

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