written 8.2 years ago by | • modified 8.2 years ago |
Mumbai university > FE > SEM 2 > Applied Physics II
Marks: 5M
Year: Dec 2015
written 8.2 years ago by | • modified 8.2 years ago |
Mumbai university > FE > SEM 2 > Applied Physics II
Marks: 5M
Year: Dec 2015
written 8.2 years ago by |
Heisenberg's uncertainty principle
The uncertainty principle discovered by Heisenberg reveals a major difference between classical and quantum mechanics.
Whereas in classical mechanics the observables are functions on phase space and therefore constitute a commutative algebra, in quantum mechanics the observables are operators, and their algebra is non-commutative.
Heisenberg's principle, stated as a mathematical theorem below, asserts that two observables of a quantum system cannot be measured simultaneously with absolute accuracy unless they commute as operators.
There is an intrinsic uncertainty in their simultaneous measurement, one that is not due simply to experimental errors.
Let us suppose that A is an observable of a given quantum system.
Thus, A is a (densely defined) self-adjoin operator on a Hilbert space H. Let ψ € H with |ψ| = 1 represent a state of the system. Then ${A}_ψ = (ψ, Aψ)$ is the expected value of the observable A in the state *.
The dispersion of A in the state ψ is given by the square root of its variance; that is
$Δ_ψA = ((A - (A)_ψ I)^2 )^{1/2} = || Aψ - (A)_ψ ψ|| $
Note that if ψ is an eigenvector of A with eigenvalue λ, then ${A}_ψ = λ $ and $△_ψ A = 0$.
Heisenberg's uncertainty principle
If A and B are observables of a quantum system, then for every state 11/ common to both operators we have
$Δ_ψ A Δ_ψ B ≥ \frac{1}{2} |[A,B]_ψ| $
Proof
Subtracting a multiple of the identity from A and another such multiple from B does not change their commentator, and it does not affect their variances.
Hence we may suppose that ${A}_ψ = {B}_ψ = 0$.
Now, we have, using the self-adroitness of both operators,
$|[A,B]_ψ| = |ψ, (AB - BA)ψ|$
$|[A,B]_ψ| = |(Aψ, Bψ) - (Bψ, Aψ)|$
$|[A,B]_ψ| = 2|Im (Aψ , Bψ)|$
But the Cauchy—Schwarz inequality tells us that
$|Im (Aψ , Bψ)| ≤ ||Aψ|| ||Bψ||$
Combining (2.2) with (2.3) yields (2.1), as desired.
A simple consequence of this result is the fact that in a quantum particle system, the position and momentum of a particle cannot be measured simultaneously with absolute certainty.