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Create an array of structure to store the details of almost 100 employees. And sort it according to employee ID. Employee details are as follows:(i) Employee Name (ii) Employee (iii) Employee salary
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Program:

#include<stdio.h>
#include<conio.h>
struct employee {
    char name[20];
    int salary, code;
};
int main() {
    struct employee e[100], temp;
    int i, j;

    for(i=0; i<=99; i++)    {
        printf("Enter the Employee's Name, Code and Salary:");
        scanf("%s %d %d", e[i].name,&e[i].code,&e[i].salary);
    }

    for(i=0; i<=98; i++)    {
        for(j=0; j<=98; j++)    {
            if(e[j].code>e[j+1].code)   {
                temp=e[j];
                e[j]=e[j+1];
                e[j+1]=temp;

            }
        }
    }
    printf("\nEmployee List:\nName\tCode\tSalary\n");
    printf("-----------------------------------------------------\n");

    for(i=0; i<=99; i++) {
        printf("%s\t%d\t%d\n",e[i].name,e[i].code,e[i].salary);
    }
    getch();
}

Output:

Enter the Employee's Name, Code and Salary:

EDEN

01

50000

Enter the Employee's Name, Code and Salary:

OSCAR

02

40000

.

.

Enter the Employee's Name, Code and Salary:

PETER

100

50000

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