Given -
¯x1=67.5 , ¯x2=68n1=1000n2=2000
Step 1 :-
Null Hypothesis (H0):μ1=μ2
Alternative Hypothesis (H∞)=μ1≠μ2
Step 2 :-
Test Statistic:-
¯x1−¯x2=67.5−68.0=−0.5
Since S.D. of the population is known
S.E.S=√σ21n1+σ22n2
=σ√1n1+1n2
=√11000+12000
=0.097
∴z=¯x1−¯x2s=−0.50.097=−5.15
∴|z|=5.15
Step 3 :- Level of significance ∝=0.27%
Step 4 :-
Critical Value
The value of Z∝ at 0.27% level of significance from table is 3
Step 5 :- Decision
Since the computed value of |z|=5.15 is greater than critical value z∝=3 the hypothesis is rejected.
∴ The sample can not be regarded as drawn from same population.